8x^2+8=35

Solution for 8x^2+8=35 equation:

8x^2+8=35

We move all terms to the left:

8x^2+8-(35)=0

We add all the numbers together, and all the variables

8x^2-27=0

a = 8; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·8·(-27)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*8}=\frac{0-12\sqrt{6}}{16}
=-\frac{12\sqrt{6}}{16}
=-\frac{3\sqrt{6}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*8}=\frac{0+12\sqrt{6}}{16}
=\frac{12\sqrt{6}}{16}
=\frac{3\sqrt{6}}{4}
$